Kilolitres per hour to Cubic meters per minute conversion

How to convert kilolitres per hour to cubic meters per minute?

Sure, I'd be happy to help you understand how to convert kilolitres per hour (kL/h) to cubic meters per minute (m³/min).

Conversion Steps

1. Understand the Units:

   • 1 kilolitre (kL) = 1 cubic meter (m³)
   • 1 hour (h) = 60 minutes (min)

2. Set Up the Conversion: To convert from kilolitres per hour (kL/h) to cubic meters per minute (m³/min), you need to convert hours to minutes.

3. Calculation:

   • Start with the given quantity: $1 \text{ kL/h}$

   • Since $1 \text{ kL} = 1 \text{ m³}$, we can rewrite this as: $1 \text{ m³/h}$

   • Now convert hours to minutes: $1 \text{ m³/h} \times \frac{1 \text{ h}}{60 \text{ min}} = \frac{1 \text{ m³}}{60 \text{ min}} = \frac{1}{60} \text{ m³/min} \approx 0.01667 \text{ m³/min}$

So, 1 kilolitre per hour is approximately 0.01667 cubic meters per minute.

Real-world Examples

Here are some examples for other quantities:

1. 5 kL/h to m³/min: $5 \text{ kL/h} = 5 \text{ m³/h}$ $5 \text{ m³/h} \div 60 = \frac{5}{60} \text{ m³/min} = 0.08333 \text{ m³/min}$

2. 10 kL/h to m³/min: $10 \text{ kL/h} = 10 \text{ m³/h}$ $10 \text{ m³/h} \div 60 = \frac{10}{60} \text{ m³/min} = 0.1667 \text{ m³/min}$

3. 50 kL/h to m³/min: $50 \text{ kL/h} = 50 \text{ m³/h}$ $50 \text{ m³/h} \div 60 = \frac{50}{60} \text{ m³/min} = 0.8333 \text{ m³/min}$

4. 100 kL/h to m³/min: $100 \text{ kL/h} = 100 \text{ m³/h}$ $100 \text{ m³/h} \div 60 = \frac{100}{60} \text{ m³/min} \approx 1.6667 \text{ m³/min}$

Practical Applications

1. Water Treatment Plants:

   • If a water treatment plant processes 500 kL/h, it would process approximately $\frac{500}{60} = 8.3333 \text{ m³/min}$.

2. Industrial Cooling Systems:

   • An industrial cooling system might circulate 200 kL/h of coolant, which is about $\frac{200}{60} = 3.3333 \text{ m³/min}$.

3. Aquarium Filtration Systems:

   • A large aquarium filter might need to circulate 50 kL/h of water, approximately $0.8333 \text{ m³/min}$.

This demonstrates how the conversion process would apply in both calculations and real-world scenarios.