bits per day (bit/day) to Bytes per second (Byte/s) conversion

What is bits per day?

What is bits per day?

Bits per day (bit/d or bpd) is a unit used to measure data transfer rates or network speeds. It represents the number of bits transferred or processed in a single day. This unit is most useful for representing very slow data transfer rates or for long-term data accumulation.

Understanding Bits and Data Transfer

• Bit: The fundamental unit of information in computing, representing a binary digit (0 or 1).
• Data Transfer Rate: The speed at which data is moved from one location to another, usually measured in bits per unit of time. Common units include bits per second (bps), kilobits per second (kbps), megabits per second (Mbps), and gigabits per second (Gbps).

Forming Bits Per Day

Bits per day is derived by converting other data transfer rates into a daily equivalent. Here's the conversion:

1 day = 24 hours 1 hour = 60 minutes 1 minute = 60 seconds

Therefore, 1 day = $24 \times 60 \times 60 = 86,400$ seconds.

To convert bits per second (bps) to bits per day (bpd), use the following formula:

$$\text{Bits per day} = \text{Bits per second} \times 86,400$$

Base 10 vs. Base 2

In data transfer, there's often confusion between base 10 (decimal) and base 2 (binary) prefixes. Base 10 uses prefixes like kilo (K), mega (M), and giga (G) where:

• 1 KB (kilobit) = 1,000 bits
• 1 MB (megabit) = 1,000,000 bits
• 1 GB (gigabit) = 1,000,000,000 bits

Base 2, on the other hand, uses prefixes like kibi (Ki), mebi (Mi), and gibi (Gi), primarily in the context of memory and storage:

• 1 Kibit (kibibit) = 1,024 bits
• 1 Mibit (mebibit) = 1,048,576 bits
• 1 Gibit (gibibit) = 1,073,741,824 bits

Conversion Examples:

• Base 10: If a device transfers data at 1 bit per second, it transfers $1 \times 86,400 = 86,400$ bits per day.
• Base 2: The difference is minimal for such small numbers.

Real-World Examples and Implications

While bits per day might seem like an unusual unit, it's useful in contexts involving slow or accumulated data transfer.

• Sensor Data: Imagine a remote sensor that transmits only a few bits of data per second to conserve power. Over a day, this accumulates to a certain number of bits.
• Historical Data Rates: Early modems operated at very low speeds (e.g., 300 bps). Expressing data accumulation in bits per day provides a relatable perspective over time.
• IoT Devices: Some low-bandwidth IoT devices, like simple sensors, might have daily data transfer quotas expressed in bits per day.

Notable Figures or Laws

There isn't a specific law or person directly associated with "bits per day," but Claude Shannon, the father of information theory, laid the groundwork for understanding data rates and information transfer. His work on channel capacity and information entropy provides the theoretical basis for understanding the limits and possibilities of data transmission. His equation are:

$$C = B \log_2(1 + \frac{S}{N})$$

Where:

• C is the channel capacity (maximum data rate).
• B is the bandwidth of the channel.
• S is the signal power.
• N is the noise power.

Additional Resources

For further reading, you can explore these resources:

• Data Rate Units: https://en.wikipedia.org/wiki/Data_rate_units
• Information Theory: https://en.wikipedia.org/wiki/Information_theory

What is Bytes per second?

Bytes per second (B/s) is a unit of data transfer rate, measuring the amount of digital information moved per second. It's commonly used to quantify network speeds, storage device performance, and other data transmission rates. Understanding B/s is crucial for evaluating the efficiency of data transfer operations.

Understanding Bytes per Second

Bytes per second represents the number of bytes transferred in one second. It's a fundamental unit that can be scaled up to kilobytes per second (KB/s), megabytes per second (MB/s), gigabytes per second (GB/s), and beyond, depending on the magnitude of the data transfer rate.

Base 10 (Decimal) vs. Base 2 (Binary)

It's essential to differentiate between base 10 (decimal) and base 2 (binary) interpretations of these units:

• Base 10 (Decimal): Uses powers of 10. For example, 1 KB is 1000 bytes, 1 MB is 1,000,000 bytes, and so on. These are often used in marketing materials by storage companies and internet providers, as the numbers appear larger.
• Base 2 (Binary): Uses powers of 2. For example, 1 KiB (kibibyte) is 1024 bytes, 1 MiB (mebibyte) is 1,048,576 bytes, and so on. These are more accurate when describing actual data storage capacities and calculations within computer systems.

Here's a table summarizing the differences:

Unit	Base 10 (Decimal)	Base 2 (Binary)
Kilobyte	1,000 bytes	1,024 bytes
Megabyte	1,000,000 bytes	1,048,576 bytes
Gigabyte	1,000,000,000 bytes	1,073,741,824 bytes

Using the correct prefixes (Kilo, Mega, Giga vs. Kibi, Mebi, Gibi) avoids confusion.

Formula

Bytes per second is calculated by dividing the amount of data transferred (in bytes) by the time it took to transfer that data (in seconds).

$$\text{Bytes per second (B/s)} = \frac{\text{Number of bytes}}{\text{Number of seconds}}$$

Real-World Examples

• Dial-up Modem: A dial-up modem might have a maximum transfer rate of around 56 kilobits per second (kbps). Since 1 byte is 8 bits, this equates to approximately 7 KB/s.

• Broadband Internet: A typical broadband internet connection might offer download speeds of 50 Mbps (megabits per second). This translates to approximately 6.25 MB/s (megabytes per second).

• SSD (Solid State Drive): A modern SSD can have read/write speeds of up to 500 MB/s or more. High-performance NVMe SSDs can reach speeds of several gigabytes per second (GB/s).

• Network Transfer: Transferring a 1 GB file over a network with a 100 Mbps connection (approximately 12.5 MB/s) would ideally take around 80 seconds (1024 MB / 12.5 MB/s ≈ 81.92 seconds).

Interesting Facts

• Nyquist–Shannon sampling theorem Even though it is not about "bytes per second" unit of measure, it is very related to the concept of "per second" unit of measure for signals. It states that the data rate of a digital signal must be at least twice the highest frequency component of the analog signal it represents to accurately reconstruct the original signal. This theorem underscores the importance of having sufficient data transfer rates to faithfully transmit information. For more information, see Nyquist–Shannon sampling theorem in wikipedia.